Creative Scratchpad

Okay, let's start with a really easy one, the first problem:

If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.

Find the sum of all the multiples of 3 or 5 below 1000.

The solution is pretty straightforward and doesn't require much of explanation, simply iterate over the numbers in the range and add those that meet the criteria. Done.

(
    local result = 0
    for i = 3 to 999 where mod i 3 == 0 OR mod i 5 == 0 do
        result += i
    result
)

It might be tempting to go right to the next problem but there's enough time for that, I don't plan on writing about more than one Euler problem a day, however simple it might be. Anyway, I promise I'll get back to other problems soon.

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